Re: dynamic file variable

Carmelo,
Thanks.  I fixed it.  Though it is irrelevant to
whether it is "linkname" or "refname", your answer did
convince me that the syntax is correct.  I moved the
code snippet to a proper place and it works.

Thanks again.

Yan
--- Carmelo Montanez <carmelo@xxxxxxxx> wrote:
> Hi:
> 
>     Try and define your variable as:
>     <xsl:variable name="refname">
>       <xsl:value-of select="@linkname"/>
>     </xsl:variable>
> 
> I think you want the "linkname" attribute NOT THE
> "refname" attribute
> (which according to your description does not exists
> in your XML source).
> 
> (As a side note, naming variables and attributes
> with the same name can lead
> to confusion)
> 
> Hope it helps,
> Carmelo Montanez
> 
> ----- Original Message -----
> From: "yan bai" <bytj@xxxxxxxxx>
> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> Sent: Monday, November 05, 2001 3:51 PM
> Subject:  dynamic file variable
> 
> 
> > I have a main.xml file, in which there is a lot of
> > <ref> elements.
> > There is an attribute "linkname" in each <ref>
> like:
> > <ref linkname="test_2.xml"/>
> >
> > In test_2.xml, there is only one root element and
> a
> > child element like:
> > <test>
> >       <sub_test link="html_test.html"/>
> > </test>
> >
> > I use the following code to get the referenced
> data:
> > <xsl:template match="ref">
> > <xsl:variable name="refname">
> >        <xsl:value-of select="@refname"/>
> > </xsl:variable>
> > <br/>
> > Here is the referenced file data:
> > <xsl:value-of
> > select="document($refname)/test/sub_test/@link"
> > />
> > </xsl:template>
> >
> > It returns null.  However, if the variable
> "$refname"
> > is replaced by the actual file name "test_2.xml",
> then
> > the data can be properly grabbed.
> >
> > Any one can tell me what is wrong?
> >
> > Thanks so much
> >
> >
> >
> >
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> >
> 
> 
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> http://www.mulberrytech.com/xsl/xsl-list
> 


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