[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Sorting outside of a for-each
Hi,
The XML I am using to create a HTML page is not generated in a sorted order. Below is a subset of the XML I am using. <country_name country_id="US">United States</country_name> <country_name country_id="US">United States Dollar</country_name> <country_name country_id="GB">United Kingdom Pound</country_name> <country_name country_id="GB">United Kingdom</country_name> <country_name country_id="FR">France Francs</country_name> <country_name country_id="FR">France</country_name> <country_name country_id="DE">Germany</country_name> <country_name country_id="DE">Germany Marks</country_name> <country_sort country_sort_id="US"> <country_sort country_sort_id="GB"> <country_sort country_sort_id="FR"> <country_sort country_sort_id="DE"> The country_name tags are not returned in a sorted order. I want to loop by the country_sort tags, because they only show 1 instance of the items in the country_name tags. If I looped by the country_name, I would duplicate my results. For my output, I want to return the country_name for the country_sort_id that excludes the currency (dollar, pounds, francs, marks). So, what I believe I want to do is a for-each on the country_sort tag and then return the first country_name field for that id, assuming the country_name tags have been sorted in ascending order. This would then ensure the name with the currency is always second. However, I have not been able to determine a process for sorting the country_name tag without a corresponding for-each. Is this possible? Thanks, Steve _________________________________________________________________ Get your FREE download of MSN Explorer at http://explorer.msn.com/intl.asp XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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