[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: xml2xml problem!
> > ********************* source xml ************************ > ... > <para> > <mediaobject> > <imageobject> > <imagedata fileref="Title00.png" format="PNG"/> > </imageobject> > </mediaobject> > <ulink url="http://www.hotmail.com/"></ulink></para> > <para> > ... > ***************** end source xml ************************ > > ********************* Output xml ************************ > ... > <para> > <ulink url="http://www.hotmail.com/"> > <imagedata fileref="Title00.png" format="PNG"/> > </ulink> > </para> > <para> > ... > ***************** end Output xml ************************ > > > How is the XSL look like if i want to convert the part of > source xml to the output xml like above ? <xsl:template match="para"> <para> <ulink url="{ulink/@url}"> <imagedata fileref="{mediaobject/imageobject/imagedata/@fileref}" format="{mediaobject/imageobject/imagedata/@fileref}"/> </ulink> </para> </xsl:template> This will transform the paragraph you've shown us correctly. Of course I have no idea if it will do anything useful with any other <para> elements, since I've no idea what those look like. Mike Kay Software AG > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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