[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] get the name of a node which I know the value
I have this xml file : <?xml version="1.0" encoding="ISO-8859-1"?> <XslParameter> <InputFile currentAuthentifiedPackageDescriptor1="C:/XML/currentAuthentifiedPackageDescriptor_N1.xml" currentAuthentifiedPackageDescriptor2="C:/XML/currentAuthentifiedPackageDescriptor_N2.xml" referenceAuthentifiedPackageDescriptor_Nectar="C:/XML/referenceAuthentifiedPackageDescriptor_Nectar.xml" automate="C:/XML/automate.xml" user="C:/XML/user_prg_dha.xml"/> <OutputFile subsetDescriptor="C:/XML/subsetDescriptor.xml" xslTrack="C:/XML/XslTrack_Test_makeSubsetDescriptor_01.xml" xslError="C:/XML/XslError_Test_makeSubsetDescriptor_01.xml"/> <Parameter signature="C:/XML/Signature.xml"/> </XslParameter> I know the value of the "currentAuthentifiedPackageDescriptor2" attribute and I would like to assign a variable with the name of the node. I tried to use name() function like this <xsl:variable name="CurrentFile" select="name()[starts-with(@*,'C:/XML/currentAuthentifiedPackageDescriptor_N2.xml')]"/> but it does not work. Please help me. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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