[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Position of a result tree fragment
Larry, Add it's original position to the rtf when you make it. Ciao Chris XML/XSL Portal http://www.bayes.co.uk/xml >-----Original Message----- >From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx >[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Laurence O >Garfield >Sent: 19 July 2001 00:08 >To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx >Subject: Position of a result tree fragment > > >If I am passing a result tree fragment from one template to another using >a variable, is there any way to determine what the fragment's position >within its parent was originally? According to the XSLT spec I can't use >/, //, or [] on result tree fragments, so I can't use [position()]. Is >there some other way, or do I have to pass the position of the node >through as a second variable as well? > >--Larry Garfield >lgarfiel@xxxxxxxxxxxxxxxxxxx > >DePaul Linux Users Group Secretary > >-- "If at first you don't succeed, skydiving isn't for you." :-) > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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