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RE: Replace a sequence of elements by an other

Subject: RE: Replace a sequence of elements by an other
From: Bedwell Tom <Tom.Bedwell@xxxxxxx>
Date: Tue, 10 Jul 2001 14:28:20 +0100
xsl replace br
This would do the trick. 
	<xsl:template match="br">
	<xsl:variable name="pos" select="position()"/>

	<xsl:choose>
		<xsl:when test="preceding-sibling::node()[position()=1 and
name()='br'] and preceding-sibling::node()[position()=2 and name()='br']">

		</xsl:when>
		<xsl:otherwise>
			<br/>
		</xsl:otherwise>
	</xsl:choose>

	</xsl:template>
-----Original Message-----

I would like to replace a sequence of  elements (in input) by an other (in
output)

As shown in the following example, when i have :
- 1 br (with or without not empty preceding text node), I keep 1 br
- 2 br, I keep 2 br
- more than 2, i keep no br



<body>
my text 1 <br />
my text 2 <br /><br />
my text 3 <br /><br /><br />
my text 4 <br /><br /><br /><br />
<table>
<tr><td> <br /><br /><br /><br /><br />
other text 
....

i would like to have in OUTPUT

<body>
my text 1 <br />
my text 2 <br /><br />
my text 3 <br /><br />
my text 4 <br /><br />
<table>
<tr><td> <br /><br />
other text 
...

How to do this?

Cheers

Pascal Troadec 



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