[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Getting date of the XSL transformation into HTML o
Hi Armin, I don't quite understand your problem. The date your XSL is generating the HTML is the current date isn't it? So why not use one of the suggestions how to get the current date and use the <xsl:value-of select="the current-date-function of your choice"/> to hardcode it into your HTML? And if you're using msxml3 (or just IE) and want to know how to pass a parameter: see my earlier mail: http://www.biglist.com/lists/xsl-list/archives/200107/msg00002.html Greetings Rene { @ @ } ^ \__/ "You don't need eyes to see, you need vision!" -----Oorspronkelijk bericht----- Van: Ghostrider [SMTP:ghostrider@xxxxxxxxxxx] Verzonden: vrijdag 20 juli 2001 9:19 Aan: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Onderwerp: Getting date of the XSL transformation into HTML output Hi list, I searched the archive and found many posts concerning GETTING THE CURRENT DATE for all sorts of purposes, usually for testing the current date against some XML content containing dates. Which is not exactly what I need to do, it's much simpler, but I don't know if it's possible: I just need to get the date my HTML output file was generated and put in a footer on that HTML page. Is there a way to do this with an XSL file without reverting to 'extension' functions? Mike Kay suggested "passing the current date in to the stylesheet as a parameter", but I'm not sure how to do this or what the exact syntax would be... Any ideas? Thanks, Armin XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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