[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Converting entities into string
Christian, The following stylesheet should work: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/DESCR"> <xsl:copy> <xsl:apply-templates/> </xsl:copy> </xsl:template> <xsl:template match="*"> <xsl:text><</xsl:text> <xsl:value-of select="name(.)"/> <xsl:text>></xsl:text> <xsl:apply-templates/> <xsl:text></</xsl:text> <xsl:value-of select="name(.)"/> <xsl:text>></xsl:text> </xsl:template> </xsl:stylesheet> Hope this helps. Bob <sig name = 'Bob Lyons' title = 'XML Consultant' company = 'Unidex, Inc.' phone = '+1-732-975-9877' email = 'boblyons@xxxxxxxxxx' url = 'http://www.unidex.com/' product = 'XML Convert: transforms flat files to XML and vice versa' /> -----Original Message----- Hello list, i need to convert a xml-file into another xml-file. I ran into this problem: Source XML: <DESCR> some text <b> more text </b> even more text </DESCR> My Target XML should look like: <DESCR> some text <b> more text </b> even more text </DESCR> i tried <xsl:copy-of> which gave me a copy of the source. <xsl:copy> removed the <b>, but I want to keep the information about the <b>, just not as <b> In short: how can i convert the '<' and '>' into '<' and '>' easily? Or is there another solution? Thanks for your help, Christian XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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