[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] passing xsl:param-values to xsl:include
Hello, i found out that constructions linke <xsl:include href="{$param}"/> doesn't work. I have to pass a parameter form an application to the xsl to include various stylesheets in dependance of the xml_owner (and his different formatting wishes). e.g. the xml_owner is no. 101 (from about 200) <xsl:stylesheet> <xsl:param name="xml_owner"/> <xsl:include="master.xsl"/> //this matches the standard templates of all owners <xsl:include="{$xml_owner}_styles.xsl"/> // this should match 1)additional templates of the owner or 2) overrriding rules for templates of the master.xsl <xsl:stylesheet> Is there any method to work this out, e.g. to write the line with the parameter dynamically? maybe with the help of a Perlscript? thanks a lot Markus XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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