[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: xsl copy
The identity transformation: <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> @* = any attribute; node() = any node(). See http://www.w3.org/TR/xslt#copying. Good luck, Mike > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of > Kevin_Gutch@xxxxxxxxxxx > Sent: Wednesday, April 25, 2001 8:39 AM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: xsl copy > > > Is there a way to copy attributes without having to perform a deep copy > (copy-of)? > > > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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