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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: XALAN - obtaining the -XSL stylesheet name?
 We use something like so...
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:include href="../document.xsl" />
<xsl:include href="../common.xsl" />
<xsl:param name="title">Edit Settings Wizard</xsl:param>
<xsl:template name="body">
...
</xsl:template>
</xsl:stylesheet>
with the document.xsl containing
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="document">
<html lang="{language/html-language}" dir="{language/html-text-direction}">
<head>
<link rel="stylesheet" type="text/css"
href="{isp/settings/css-base}/{isp/settings/css-url}.css"/>
<title><xsl:value-of select="$title"/></title>
</head>
<body>
...
<xsl:call-template name="body"/>
...
</body>
</html>
</xsl:template>
</xsl:stylesheet>
This passes the param "title" to the html for use in the external
stylesheet, simular to how you want to pass a param to your external
stylesheet.
This can be directly duplicated into your style sheet in the same way. The
param is just declared in the first stylesheet and can be used in the
external one.
best wishes,
Tim Watts
-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Robert
Nicholson
Sent: Thursday, 29 March 2001 2:20 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: XALAN - obtaining the -XSL stylesheet name?
Currently I have
resume-us-html.xsl defined as such
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:import
href="http://localhost:8080/jobserve/jsp/resume-common-html.xsl"/>
<xsl:output method="html" indent="yes"/>
<xsl:template match="contact-information">
...
<xsl:apply-templates select="us-address"/>
</xsl:template>
<xsl:template match="us-address">
<address>
...
</address>
</xsl:template>
<xsl:template match="start-date">
...
</xsl:template>
</xsl:stylesheet>
Notice the import
Now the document element's (<resume>) template rule is defined in my common
stylesheet thus
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="resume">
<html>
<head>
<title>Resume</title>
</head>
<body onLoad="pagePopUp("url derived from stylesheet name")>
I want the url argument of pagePopUp of the resulting html to be derived
from the stylesheet that I'm passing as -XSL to XALAN which is the same
stylesheet that's importing the common stylesheet.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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