[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Absolute position
count( (preceding::node()|ancestor::node()) [count(. | $p/descendant::node()) = count($p/descendant::node()) ] ) where $p contains some single ancesstor of the current node. Carmelo Montanez wrote Thanks Wendell ...... Almost there ..... however, I want to constraint the selection a bit more, look at a more descriptive tree. I want to select the position within each "parent" subtree. In other words "child3" is number 5 within the first "parent" subtree but it will be number 6 at the second "parent" subtree. __________________________________________________ Do You Yahoo!? Get email at your own domain with Yahoo! Mail. http://personal.mail.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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