[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Copy XHTML element contents without base tag
> Now, as far as I can see there are two ways of processing > this in XSLT: > > <xsl:template match="xfragment"> > <xsl:copy-of select="." /> > </xsl:template> > > Unfortunately this ends up including the <xfragment> tags in > the output, > which I can't really have. > > The other way I can see is > > <xsl:template match="xfragment"> > <xsl:copy-of select="./*" /> > </xsl:template> > > Unfortunately this removes any text elements which are direct > children of > the xfragment tags (e.g. the phrase 'This is a fragment of > XHTML' in the > above example). > > Does anyone know any better ways of making this copy? > <xsl:template match="xfragment"> <xsl:copy-of select="node()" /> </xsl:template> Mike Kay Software AG XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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