RE: How to "quo" without "quo"

Lindy,

I think you want the div operator. See section 3.2 of the XPath spec for
more details (http://www.w3.org/TR/xpath#numbers).

gl,

-Mike

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Lindy Quick
> Sent: Thursday, March 08, 2001 2:29 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE:  How to "quo" without "quo"
>
>
> That returns the remainder.  I am in need of the quotient.
> Lindy
>
> -- Original Message --
>
> >Every time I've seen an example like that it's been "... mod 2".
> >
> >PC2
> >
> >-----Original Message-----
> >From: Lindy Quick [mailto:lindyq@xxxxxxxx]
> >Sent: March 8, 2001 14:07
> >To: XSL List
> >Subject:  How to "quo" without "quo"
> >
> >
> >Hello,
> >
> >I have found previous examples of the "quo" operator, but I realize that
> >it is no longer in the standard.  Can anyone tell me why it was removed
> >and how to perform its functionality another way?
> >
> >I am trying to calculate the median, and am having problems.  I think the
> >way it will have to be done is to sort the list, count the list, divide
> >the count by 2 returning a whole number, and then select the position of
> >the divided count.  This is what I am attempting to do below, but it is
> >not working.
> >
> ><xsl:for-each select="profile-table/row/Whole-request">
> >  <xsl:sort data-type="number" order="descending"/>
> >  <xsl:if test="position()=count(profile-table/row) quo 2">
> >    <xsl:value-of select="."/>
> >  </xsl:if>
> ></xsl:for-each>
> >
> >If I set the position to a static number it is fine.  I have also tried
> >checking just the count(profile-table/row) quo 2 and that is how I found
> >out that quo no longer exists in the standard.
> >
> >I look forward to any help you can provide.
> >Thanks in advance
> >Lindy Quick
> >
> >
> >
> >
> >--
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> >
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>
>
>
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