Re: doctype

Gerhard,

You cannot access the DOCTYPE from XSLT (the only info from the DTD
that's available is about the ID attributes).

A workaround is to access DOCTYPE from your script (e.g. via DOM) and
to set the necessary value as parameter to the stylesheet, before
invoking transformNode().

Another one -- use schema instead of a DTD.

Dimitre Novatchev.

----------------------- Original Message -----------------------
To: xsl-list at mulberrytech dot com 
Subject: doctype 
From: STENZEL at de dot ibm dot com 
Date: Fri, 24 Nov 2000 16:29:30 +0100 
Reply-To: xsl-list at mulberrytech dot com 

--------------------------------------------------------------------------------



Hi, I am trying to find out the doctype , i.e top level element name,
in
order to load an additional file, whose name is based on the doctype.
Example: If the doctype were 'something', the additional file would be
called 'somethingelse.xml'
Problem is now that the variable holding this value must have global
scope.
How do I acces the name of the top level element?
I think it should close to the following, but I am still missing the
???
part?
  <xsl:variable name="DocType">
    <xsl:value-of select="???"/>
  </xsl:variable>
  <xsl:variable name="RecordLayouts" select="document(concat($DocType,
'else.xml'))"/>

Thanks for any suggestions...

Best regards,
Gerhard Stenzel





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