[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: How to declare a param which name is in a XML file?
Lots of confusion here, I think. The original posting, which I was answering, contained the XML/XSL below. I responded with why I thought the error was occurring. Now others are responding to me, personally and through the list, as if it were a question from me. The original question of why it didn't work was posted by Cesar Hernandez Fuente on Thursday. I wrote an answer, at which point several people pointed the question back at me and tried to answer "my" question. Just thought I'd clear that up. Perhaps I will word my responses better in the future to make it clear when a posting is a question vs. an answer. I think that Cesar has his answer, though, which shows that all's well that ends well. Don >-----Original Message----- >From: Kay Michael [mailto:Michael.Kay@xxxxxxx] >Sent: Friday, October 27, 2000 10:20 AM >To: 'xsl-list@xxxxxxxxxxxxxxxx' >Subject: RE: How to declare a param which name is in a XML file? > > >> The XSL in the original message was this: >> >> 1) <xsl:template match="parameters"> >> 2) <xsl:for-each select="param"> >> 3) <xsl:param name="@ident"/> >> 4) </xsl:for-each> >> 5) </xsl:template> >> >> MSXML3 says: "Keyword xsl:param may not be used here." >> >> (Instant) Saxon says: "Failed to compile style sheet. At >> xsl:param on line 6 >> of file:/c:\test.xml: Name @ident contains invalid >> characters" > >They are both right: both errors are present in the stylesheet, the two >processors have just done their checking in a different order. > >Mike Kay > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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