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RE: XSL attribute expression

Subject: RE: XSL attribute expression
From: "Evan Lenz" <elenz@xxxxxxxxxxx>
Date: Wed, 4 Oct 2000 18:09:25 -0700
xsl attribute url
Your code should work.  What processor are you using?  If you're using IE5,
you need to install the MSXML3 upgrade and install in "replace mode".  Read
this FAQ:

http://www.netcrucible.com/xslt/msxml-faq.htm

Evan Lenz
elenz@xxxxxxxxxxx
http://www.xyzfind.com
XYZFind, the search engine *designed* for XML
Download our free beta software: http://www.xyzfind.com/beta


-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxx]On Behalf Of Dwight Kelly
Sent: Wednesday, October 04, 2000 4:34 PM
To: xsl-list@xxxxxxxxxxxxxxxx
Subject: XSL attribute expression



I am fairly new to XSL and am trying to extract the value of the attribute
'url' from the node 'job' and make it a HTML <A HREF=> link. Is this the
correct syntax? Instead of getting
<A HREF="http://www.apago.com/jobs/1">URL</A>
I am getting
<A HREF="{@url}">URL</A>

here is my xml file fragment:

<job job-id="100" url="http://www.apago.com/jobs/1" />

and my xsl fragment:

<xsl:template match="job">
	<DIV>
	Job <xsl:value-of select="@job-id" />
	<A HREF="{@url}">URL</A>
	</DIV>
</xsl:template>

Thanks,
--
Dwight Kelly
Apago, a division of Essential Technical Services, Inc.
315 Allen Street Cumming, GA 30040
voice:(770) 889-2848  fax:(770) 889-2624 Internet:dkelly@xxxxxxxxx
http://www.apago.com


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