[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Using xsl:if to determine if a node is empty.
I am fairly new to XML/XSL. In fact I am writing my first XSL for a production environment. I am trying to determine if a node is empty so that I can print a line or not. I have tried several different variations of template matching and xsl:if statements and have not been able to get anywhere. Here is the latest thing that I have tried which seems to match evertime through so the text is coming out even on empty tags. <xsl:template match="VENDOR_ITEM_NUM"> <xsl:variable name="empty_tag"></xsl:variable> <tr> <td></td> <td> <font size="2"> <xsl:if test="$empty_tag != ."> <xsl:value-of select="concat('Vendor Item number: ',.)"/> </xsl:if> </font> </td> </tr> </xsl:template> Any help would be greatly appreciated. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|