Re: XSLT enhancement requests

> how do you, in XSLT, pick up the fact that both elements have, in terms
> of XML Schema semantics, the same value for their "type" attribute?

Oh, I see what you mean. Doable, but not particularly beautiful...
Actually it highlights a possible problem with providing built in
functions for this, as xpath semantics would be different, if they were
xpath attributes they would be in different namespaces as the default
namespace doesnt apply to xpath, so a built in xpath function (which
would presumably follow xpath semantics) wouldn't necessarily do the
right thing.

Here's your example, wrapped into one file for simplicity, and extended
a bit to test the following stylesheet.


<x>

<xsd:schema xmlns:xsd="http://www.w3.org/1999/XMLSchema">
	<xsd:element name="swissBankAccountNo" type="xsd:string"/>
</xsd:schema>


<schema xmlns="http://www.w3.org/1999/XMLSchema">
	<element name="luxembourgBankAccountNo" type="string"/>
</schema>

<xsd:schema xmlns:xsd="http://www.w3.org/1999/XMLSchema">
	<xsd:element name="englishBankAccountNo" type="xsd:string2"/>
</xsd:schema>


<schema xmlns="http://www.w3.org/1999/XMLSchema">
	<element name="frenchBankAccountNo" type="string2"/>
</schema>

<xsd:schema xmlns:xsd="file:/notschema">
	<xsd:element name="swissBankAccountNo" type="xsd:string"/>
</xsd:schema>


<schema xmlns="file:/notschema">
	<element name="luxembourgBankAccountNo" type="string"/>
</schema>

</x>





<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                version="1.0"
              xmlns:xsd="http://www.w3.org/1999/XMLSchema"
                >
<xsl:strip-space elements="*"/>

<xsl:output method="text" />

<xsl:template match="xsd:element">

Element name <xsl:value-of select="@name"/>
   type=<xsl:text/>
<xsl:variable name="p">
<xsl:if test="contains(@type,':')">
  <xsl:value-of select="substring-before(@type,':')"/>
</xsl:if>
</xsl:variable>

<xsl:variable name="n">
<xsl:choose>
<xsl:when test="contains(@type,':')">
  <xsl:value-of  select="substring-after(@type,':')"/>
</xsl:when>
<xsl:otherwise>
  <xsl:value-of  select="@type"/>
</xsl:otherwise>
</xsl:choose>
</xsl:variable>

<xsl:variable name="ns" select="namespace::*[name()=$p]"/>

  <xsl:text>{</xsl:text>
  <xsl:value-of select="$ns"/>
  <xsl:text>}</xsl:text>
  <xsl:value-of select="$n"/>
   Elements with the same type are:
    <xsl:for-each select="//xsd:element">
<xsl:variable name="p2">
<xsl:if test="contains(@type,':')">
  <xsl:value-of select="substring-before(@type,':')"/>
</xsl:if>
</xsl:variable>

<xsl:variable name="n2">
<xsl:choose>
<xsl:when test="contains(@type,':')">
  <xsl:value-of  select="substring-after(@type,':')"/>
</xsl:when>
<xsl:otherwise>
  <xsl:value-of  select="@type"/>
</xsl:otherwise>
</xsl:choose>
</xsl:variable>
<xsl:variable name="ns2" select="namespace::*[name()=$p2]"/>

<xsl:if test="$n=$n2 and $ns=$ns2">
  <xsl:value-of select="@name"/><xsl:text>&#10;    </xsl:text>
</xsl:if>
</xsl:for-each>

</xsl:template>
</xsl:stylesheet>


ash-2.01$ saxon nsstring.xml nsstring.xsl


Element name swissBankAccountNo
   type={http://www.w3.org/1999/XMLSchema}string
   Elements with the same type are:
    swissBankAccountNo
    luxembourgBankAccountNo
    

Element name luxembourgBankAccountNo
   type={http://www.w3.org/1999/XMLSchema}string
   Elements with the same type are:
    swissBankAccountNo
    luxembourgBankAccountNo
    

Element name englishBankAccountNo
   type={http://www.w3.org/1999/XMLSchema}string2
   Elements with the same type are:
    englishBankAccountNo
    frenchBankAccountNo
    

Element name frenchBankAccountNo
   type={http://www.w3.org/1999/XMLSchema}string2
   Elements with the same type are:
    englishBankAccountNo
    frenchBankAccountNo


David


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