[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: retrieving a piece of data from a different xml file
When I try to display my page in IE5 the following data generates "The XML page cannot be displayed. Cannot view XML input using XSL style sheet.... Unspecified error..." The line it references is completely unrelated, but when I comment out the link template (which is what I'm trying to get to work correctly), everything displays correctly. Can someone point out where I've gone wrong (in novice terms please!) Thanks much! Eric : ) In XML: <link page="test1" text="link to test1"/> In XSL: <xsl:template match="link"> <xsl:if test="@page"> <xsl:variable name="locs" select="document('\docs\pagelocations.xml')"></xsl:variable> <A> <xsl:attribute name="href"> <xsl:value-of select="$locs/pages/page[@name = current()/@page]/@location" /> </xsl:attribute> <xsl:attribute name="target">new_window</xsl:attribute> <xsl:value-of select="@text"/> </A> </xsl:if> </xsl:template> In \docs\pagelocations.xml: <?xml version="1.0"?> <pages> <page name="test1" location="d:\xml\test\test1.xml"/> <page name="test2" location="d:\xml\test\test2.xml"/> </pages> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|