[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Selection of an XML-Tree will not work
Hi, I have confused Problem with XPath. Im trying to create a XPath statement to select a subsection of an XML-Tree. Please let me you give first a example of the tree. <tree> <entry id="1"> <entry id="A"> <entry/> <entry id="2"> <entry id="B"> <entry id="I"/> <entry/> <entry id="C"> <entry id="J"/> <entry/> <entry/> <entry id="3"> <entry id="D"> <entry/> </tree> Ok fine - thats the tree. And now let me describe how I would select the tree. My wish is it - I would say give me all ancestor and from one of the anscestors element all childs. I give you now a little example. When I say select me the Tree for ID="I" it should me select the following tree. <tree> <entry id="1"/> <entry id="2"> <entry id="B"> <entry id="I"/> <entry/> <entry id="C"/> <entry/> <entry id="3"/> </tree> You see - it selects all elements from depth=1, but no subelement from id="1" and id="3", and in depth=2, only subelements from id="B", but no subelements from id="C". Ok this is what I want - and I have also a code that worked, here is the code example: <xsl:template match="tree"> <xsl:for-each select="//*"> <xsl:if test="$navid=string(@id)"> <xsl:if test="boolean(@title)"> <xsl:variable name="subid"> <xsl:number level="multiple" format="A."/> </xsl:variable> <xsl:for-each select="//*"> <xsl:variable name="curid"> <xsl:number level="multiple" format="A."/> </xsl:variable> <xsl:variable name="curid"> <xsl:value-of select="substring($curid,0,string-length($curid)-1)"/> </xsl:variable> <xsl:if test="starts-with($subid,$curid)"> <xsl:value-of select="@id"/><br/> </xsl:if> </xsl:for-each> </xsl:if> </xsl:if> </xsl:for-each> </xsl:template> $navid is a variable who is set the ID what should selected. This code worked fine but I hope you can tell me how I can select the same Path with XPath. - Conny - XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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