Re: format the date

In message <200006240843.KAA03336@xxxxxxxxxxxxxxxxx>, SAUREL Eric
<Eric.SAUREL@xxxxxxxxxxx> writes
>hi,
>i have : <date format="ISO-8601">2000-05-24</date>
>how can i have the date on this format : Vendredi 24 juin 2000
>[ i am french ].
>where i can find some informations about this.
>thank for your help.

This code (not tested, although it's based on a routine which has been)
should output "24 mai 2000" [sic] for the date you specify.  I haven't a
clue how to derive the day of the week in XSLT!

<xsl:template name="convertMonth">
  <xsl:variable name="month-as-number" select="number(substring-
before(substring-after(text(), '-'), '-'))"/>
  <xsl:choose>
    <xsl:when test="$month-as-number=1">janvier</xsl:when>
    <xsl:when test="$month-as-number=2">f&eacute;vrier</xsl:when>
    <xsl:when test="$month-as-number=3">mars</xsl:when>
    <xsl:when test="$month-as-number=4">avril</xsl:when>
    <xsl:when test="$month-as-number=5">mai</xsl:when>
    <xsl:when test="$month-as-number=6">juin</xsl:when>
    <xsl:when test="$month-as-number=7">juillet</xsl:when>
    <xsl:when test="$month-as-number=8">ao&ucirc;t</xsl:when>
    <xsl:when test="$month-as-number=9">septembre</xsl:when>
    <xsl:when test="$month-as-number=10">octobre</xsl:when>
    <xsl:when test="$month-as-number=11">novembre</xsl:when>
    <xsl:when test="$month-as-number=12">decembre</xsl:when>
    <xsl:otherwise><xsl:value-of select="concat('[invalid month: ',
'$month-as-number')"/></xsl:otherwise>
  </xsl:choose>
</xsl:template>

<xsl:template xml:space="preserve" match="date[@format='ISO-8601']">
  <xsl:value-of select="substring-after(substring-after(text(), '-'),
'-')"/>
  <xsl:call-template name="convertMonth"/>
  <xsl:value-of select="substring-before(text(), '-')"/>
</xsl:template>

Hope this helps,

Richard Light.

Richard Light
SGML/XML and Museum Information Consultancy
richard@xxxxxxxxxxxxxxxxx


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list