RE: several questions on XML to HTML processing with XSL

Hello,

> From: Kay Michael <Michael.Kay@xxxxxxx>
> Date: Fri, 9 Jun 2000 15:50:14 +0100 
>> 4. How do I declare a variable parametername?
>> 
>> I'd like to do the following, but Saxon returns an errormessage on the
>> <xsl:with-param> line (invalid $ character).
>> 
>> <xsl:variable 
>> name="ParamName">someXMLtag/@someAttribute</xsl:variable>
>> 
>> <xsl:call-template name="SomeTemplateName">
>>    <xsl:with-param name="$ParamName">whateverValue</xsl:with-param>
>> </xsl:call-template>
>> 
>> How should I do this?

>Leave out the "$" sign. It's not part of the parameter's name, it's only
>used to identify a variable when used within an XPath expression.


Sorry, I left something out. The template 'SomeTemplateName' has several
parameters which I initialised to
a default value and I only want to set one to a different value, but this
one parameter can be variable.

So it's something like this:

<xsl:template name="SomeTemplateName">
<xsl:param name="param1">true</xsl:param> 
<xsl:param name="param2">true</xsl:param>
<xsl:param name="param3">true</xsl:param>
<xsl:param name="param4">true</xsl:param>

<!-- do some processing here based on the value of the parameters -->

</xsl:template>

the variable "ParamName" will be either "param1", "param2" etc. and
'whateverValue' could be e.g. 'false'.

So instead of passing on the value of all parameters I just want to pass on
the only parameter that's changed.

I vaguely recall that someone has once asked a similar question, but I can't
find it in the archives.

Bye,

Helma van der Linden
Medical Informatics
h.vanderlinden@xxxxxxxxxxxxx 


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