[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: selecting a node without its children
You can use @id to get the attribute value in ur XSL like this <xsl:template match="/"> <xsl:for-each select="STORY"> <xsl:for-each select="AUTHOR"> <xsl:value-of select="@id"/> </xsl:for-each> </xsl:for-each> </xsl:template> Francis > -----Original Message----- > From: Ben Sorek [mailto:bsorek@xxxxxxxxxxxxx] > Sent: Thursday, March 30, 2000 6:39 PM > To: xsl-list@xxxxxxxxxxxxxxxx > Subject: RE: selecting a node without its children > > > This is my XML > > <STORY> > <AUTHOR id="xsw">Stephen King</AUTHOR> > </STORY> > > If I have a template > > <xsl:template match="STORY"> > .... > </xsl:template> > > how can i get the id attribute of author inside that template? > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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