[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: selecting a node without its children
Mike, This is not working for me.Why?.I have to use <xsl:template match="/"> <xsl:for-each select="STORY"> <xsl:for-each select="AUTHOR"> <xsl:value-of select="@id"/> </xsl:for-each> </xsl:for-each> </xsl:template> Where exactly the code u gave will work?. Thanx, Francis > -----Original Message----- > From: Kay Michael [mailto:Michael.Kay@xxxxxxx] > Sent: Thursday, March 30, 2000 7:07 PM > To: 'xsl-list@xxxxxxxxxxxxxxxx' > Subject: RE: selecting a node without its children > > > > This is my XML > > > > <STORY> > > <AUTHOR id="xsw">Stephen King</AUTHOR> > > </STORY> > > > > If I have a template > > > > <xsl:template match="STORY"> > > .... > > </xsl:template> > > > > how can i get the id attribute of author inside that template? > > <xsl:value-of select="AUTHOR/@id"/> > > Mike Kay > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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