[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Simple XPath question
> Is there a way in XPath to find all PERSON's such that there exists > another PERSON such that the two people have identical @firstname and > @lastname attributes? Let's try to do it : I presume the source XML document is : <PERSON firstname="fn1" lastname="ln1"/> <PERSON firstname="fn2" lastname="ln2"/> <PERSON firstname="fn2" lastname="ln2"/> <PERSON firstname="fn3" lastname="ln3"/> <PERSON firstname="fn4" lastname="ln4"/> <PERSON firstname="fn3" lastname="ln3"/> and the target is : <PERSON firstname="fn2" lastname="ln2"/> <PERSON firstname="fn3" lastname="ln3"/> right ? Then a solution is : <xsl:template match="PERSONS"> <xsl:apply-templates select="PERSON[following-sibling::PERSON/@lastname = ./@lastname and following-sibling::PERSON/@firstname = ./@firstname]"/> </xsl:template> Sebastien XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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