Re: Dependency Sorting, first of kind

James Clark wrote:
> 
...
> 
> $a | $b returns the set of nodes that are members of $a or $b. If this
> is what you mean by set union, then the set intersection of $a and $b
> should be the set of nodes that are members of both $a and $b. But $a[.
> = $b] does not return this; it returns the nodes in $a for which there
> is a node in $b with the same value.
> 
Yes, I confused objects with values. I read this just in time to save my
sanity as to why my simple set demo wasn't working. Everything goes
horribly wrong when you start operating on the values of empty elements
- very non-unique...


Francis.


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