[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: xsl: descendent count?
Hi there, My <xsl:if> condition is working. I tried hard and now I got success. Refer to following mail and you understand the following code. Source XML:- <CHAPTER> <PARA/> <PARA/> <PARA/> </CHAPTER> XSL FILE:- <xsl:variable name="CHILD"> <xsl:value-of select="count(para)"/> </xsl:variable> <xsl:if test="['$CHILD>0']"> <xsl:if> Thanx, everybody who helped me. **************************** Surendra Moghe surendra_moghe@xxxxxxxxxxxx **************************** smoghe@xxxxxxxxxxxx@m... on 09/16/99 04:28:24 PM Please respond to xsl-list@xxxxxxxxxxxxxxxx Sent by: owner-xsl-list@xxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxx cc: Subject: Re: xsl: descendent count? > How can I get CHILDREN count of an element. <xsl:value-of select="count(*)"/> for all children, or <xsl:value-of select="count(PARA)"/> to tell you how many PARA children the current node has. David ------------------ Thanx David, But still, I'm not able to compare the condition, I tried a lot. e.g. <xsl:if test='["cout(*)>5"]'> <xsl:if> The above condition is not working, can you help me out. Thanx, in advance. **************************** Surendra Moghe surendra_moghe@xxxxxxxxxxxx **************************** XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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