[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message]

Re: How can I get real path ?

Subject: Re: How can I get real path ?
From: "Amit Rekhi" <amitr@xxxxxxxxxxxxx>
Date: Wed, 1 Jul 1998 10:11:14 +0530
load xml file real path
Benoît,

>'path(this)' can't give me what I want.
>path gives me :
>1 description
>1.1 document
>1.1.1 name
>1.1.1 status  // <= that's not what I want
>
Path() will not , coz path() returns an array of numbers including number of
the element w.r.t. all of its siblings (of its type)......... (Read the
MSXSL tutorial Lesson#23)
Therefore name and status will be given the same number 1.1.1

>I can't figure out how to do that. Is there any other solution ?
Well, u could use XMLDSO to load the XML file, then access the parse
tree(containing the XML elements at each level) using scripts and
programatically generate the numbering functionality....

            Hope it helps,


AMIT
Current Thread

PURCHASE STYLUS STUDIO ONLINE TODAY!

Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!

Buy Stylus Studio Now

Download The World's Best XML IDE!

Accelerate XML development with our award-winning XML IDE - Download a free trial today!

Don't miss another message! Subscribe to this list today.
Email
First Name
Last Name
Company
Subscribe in XML format
RSS 2.0
Atom 0.3
Site Map | Privacy Policy | Terms of Use | Trademarks
Free Stylus Studio XML Training:
W3C Member
Stylus Studio® and DataDirect XQuery ™are products from DataDirect Technologies, is a registered trademark of Progress Software Corporation, in the U.S. and other countries. © 2004-2013 All Rights Reserved.