[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] How can I get real path ?
Imagine I have the following XML instance : <?xml version="1.0"?> <description> <document> <name>a name</name> <status>a status</status> <name>a name</name> </document> </description> I want to get something like : 1 description 1.1 document 1.1.1 name 1.1.2 status 1.1.3 name 'path(this)' can't give me what I want. path gives me : 1 description 1.1 document 1.1.1 name 1.1.1 status // <= that's not what I want I can't figure out how to do that. Is there any other solution ? Note : I use MSXSL.Exe. benoit.barre@xxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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