Good point in general, but is there a good and easy way to use XProc 3
from/with Python ?

Am 01.07.24, 16:30 schrieb "Piez, Wendell A. (Fed) wendell.piez@xxxxxxxx"
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>:

  Hello,

  Or, today, to process HTML into an XSLT pipeline, one might opt for
  XProc 3.0.

  What with plain-text, JSON and HTML inputs, and with XSLT streaming
  and accumulators, maybe XSLT has finally caught up with Omnimark?

  Regards, Wendell

  -----Original Message-----
  From: Martin Honnen martin.honnen@xxxxxx
  <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
  Sent: Sunday, June 30, 2024 4:51 PM
  To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
  Subject: Re:  Rexsel b A simpler way of writing XSLT

  On 30/06/2024 19:20, Chris Papademetrious chrispitude@xxxxxxxxx
  wrote:
  > Nowadays I mostly process HTML in Python. The funny thing is, I
  would
  > kill for a way to natively process HTML5 in XSLT (without resorting
  to
  > XHTML) because the content processing I do would fit a template
  based
  > approach very well. But alas, there's no easy way in the Python
  world.

  If you have a Saxon PE or EE license you can use SaxonCPE or SaxonCEE
  (https://pypi.org/project/saxoncee/< /a>) with Python and use the
  parse-html extension/XPath 4 function to process HTML5 with XSLT
  4/XQuery 4 (and until we see 12.5 with XPath if you use the hack of
  https://saxonica.plan.io/i ssues/5967#note-8).

  parse-html(unparsed-text("https://stackoverflow
  .com/questions/tagged/saxon"))

  Your mileage of "easy way" might differ.

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