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Am 09.05.2020 um 13:59 schrieb Costello, Roger L. costello@xxxxxxxxx:
Hi Folks,n. number($B/col[$i])) of these computations, so I want to use the most efficient approach. You can express it a bit more nicely in XPath 3 with higher-order functions as sum(for-each-pair($A/col, $B/col, function($a, $b) { $a * $b})) but whether that performs better or worse is something you can only measure.
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