Hi Folks,

My XSLT program has a variable $filename which contains the name of an XML
file. The XML file is in a folder named "files" or one of its subfolders or
one of its sub-subfolders or one of its sub-sub-subfolders or ...

In other words, it's somewhere in the tree of folders rooted at "files."

I want to open the XML file (wherever it's located within "files") and read it
into an XSLT variable. Is there a way to do this?

/Roger