Am 06.11.2019 um 15:50 schrieb Flanders, Charles E (US)
charles.flanders@xxxxxxxxxxxxxx:

I need help with an issue that I haven't come across before and I'm not even

sure that I have the subject correct. I am working with XSLT 2.0. Please no
3.0 solutions.

Which XSLT 2 processor do you use, any access to a proprietary
"serialize" function? Otherwise I guess you will need to write a
function computing some fingerprint, I think Dimitre has posted
solutions on that in the past here.

I have a long list of <mac-group-2lvl> structures as below. Most are

unique. However in some cases, they are identical except for the "ref"
attribute value on the <teref>  element.

Write a function that pushes each element through a mode that strips
that attribute, then let it serialize the result or compute a
fingerprint, then use that fingerprint or serialization in
group-adjacent or group-by of for-each-group, pushing the context node
(i.e. first item in a group) through the identity transformation with
the collected

B B B B B B B B B B B B B B B B B B B B B  <xsl:with-param name="refs"
tunnel="yes"
select="current-group()//terefs/teref"/>

B  <xsl:template match="mac">
B B B B B  <xsl:copy>
B B B B B B B B B  <xsl:apply-templates select="@*"/>
B B B B B B B B B  <xsl:for-each-group select="*"
group-adjacent="mf:finger-print(.)">
B B B B B B B B B B B B B  <xsl:copy>
B B B B B B B B B B B B B B B B B  <xsl:apply-templates>
B B B B B B B B B B B B B B B B B B B B B  <xsl:with-param name="refs"
tunnel="yes"
select="current-group()//terefs/teref"/>
B B B B B B B B B B B B B B B B B  </xsl:apply-templates>
B B B B B B B B B B B B B  </xsl:copy>
B B B B B B B B B  </xsl:for-each-group>
B B B B B  </xsl:copy>
B  </xsl:template>

B  <xsl:template match="teref">
B B B B B  <xsl:param name="refs" tunnel="yes"/>
B B B B B  <xsl:sequence select="$refs"/>
B  </xsl:template>