If I read this right, it looks like you just want to generate a list of the
XML files in a directory, is that correct?  If youbre in a windows
enviroment the bdirb command will do what you want.

Michele

From: Rahul Singh rahulsinghindia15@xxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, January 14, 2019 11:45 AM
To: XSL-List: The Open Forum on XSL <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>;
xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  bat file creation based on xsl /xml

Hi,

I want to create .bat file for below logic, i have xml input in 1 directory.
how to do?:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:fn="http://www.w3.org/2005/xpath-functions" exclude-result-prefixes="xs
fn">
            <xsl:output method="text" version="1.0" encoding="UTF-8"
indent="no"/>
            <xsl:template match="/">
                        <xsl:for-each select="collection('.?select=*.xml')">
                                    <xsl:text>&#10;</xsl:text>
                                                <xsl:value-of
select="document-uri(.)"/>
                                    </xsl:variable>
                                    </xsl:for-each>
            </xsl:template>
</xsl:stylesheet>

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