Am 08.03.2018 um 07:36 schrieb Dr. Patrik Stellmann patrik.stellmann@xxxxxxxxx:

Hi,

a question more motivated by curiosity than by a real problem:

With

<xsl:sequence select=ba, bb/>

I will get first element a and second element b b no matter of the order within the input document.

But with

<xsl:sequence select=broot/(a, b)b/>

I will get the elements a and b in document order. So this behaves identical to

B B B B B B B B B B B <xsl:sequence select=broot/(a | b)b/>

Why?

Of course I could write

<xsl:sequence select=broot/a, root/bb/>

To ensure a specific order. But sometimes the expression of brootb is much more complex so Ibd like to avoid writing it twice or putting it in a variableb&

You can move to XPath/XSLT 3 and use the "!" operator

B root!(a, b)



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