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On 26/09/2012 12:19, Ihe Onwuka wrote: > On Thu, Sep 20, 2012 at 7:13 AM, Ihe Onwuka > <ihe.onwuka@xxxxxxxxxxxxxx> wrote: >> It would seem (somewhat paradoxically) that given the definition >> of position() and last() they could be applied to @* which is >> intrinsically unordered. > > So seeking to output all the attributes of an element comma > separated (by all means correct me if I miss the obvious). > > If I have done apply-templates select="@*" and have > > <xsl:template match="@*"> < code to output the attribute> <!-- do I > put a comma or not --> <xsl:if test=". is ../@*[last()]>,</xsl:if>
node-set is Xpath 1 terminology. As we tried to explain before the XDM model over which the stylesheet is operating consists of _ordered_ sequences of nodes. The sequence of attribute nodes for the element is fixed for the lifetime of the XDM model that was built at parse time, so each time you select @*[last()] on the same element you get the same attribute. > > So either I have to put the @* in a variable and do my if test on > that to ensure I am dealing with the same node-set or I match on > the parent element instead of @* and for-each through @* and decide > where to put my commas that way. Not really see above. > > Or have I got that wrong. > I think, yes. David -- google plus: https:/profiles.google.com/d.p.carlisle ________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. ________________________________________________________________________
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