Subject: Re: XPath question concerning distinct-values()
From: Michael Kay <mike@xxxxxxxxxxxx>
Date: Fri, 03 Aug 2012 14:20:39 +0100
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It's simplest to use xsl:for-each-group for this.
<xsl:template match="pricelist">
<xsl:for-each-group select="item" group-by="order-number">
<xsl:value-of select="current-group()[1]/(order-number, price),
'
'"/>
</xsl:for-each-group>
</xsl:template>
Michael Kay
Saxonica
On 03/08/2012 12:14, Thorsten wrote:
Hello,
I have a terrible SAP export that looks (simplified) like this:
<pricelist>
<item>
<title>Lorem Ipsum Dolor Sit Amet</title>
<order-number>XY7020280901</order-number>
<price>12.00</price>
<unit>50</unit>
</item>
<item>
<title>Some Title</title>
<order-number>XY9010200901</order-number>
<price>19.00</price>
<unit>50</unit>
</item>
<item>
<title>The Same Item With A Different Title</title>
<order-number>XY9010200901</order-number>
<price>19.00</price>
<unit>50</unit>
</item>
<item>
<title>Lorem Ipsum Dolor</title>
<order-number>XY7010220201</order-number>
<price>18.00</price>
<unit>50</unit>
</item>
</pricelist>
I want to select each <item> with different <order-number>. Simply
distinct-values(/pricelist/item) doesn't work because the <title> of item[2] and
item[3] are different.
My output should look like this:
XY7020280901 12.00
XY9010200901 19.00
XY7010220201 18.00
I'm using XSLT2.0 with Saxon 9.2 PE.
Any ideas?
Many thanks in advance.
Kind regards
Thorsten
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