<xsl:template match="fault">
        <xsl:copy>
            <xsl:variable name="q" as="xs:QName" select="." />
            <xsl:attribute name="{local-name-from-QName(q)}" namespace="namespace-uri-from-QName(q)">blah</xsl:attribute>
            <xsl:value-of select="." />
        </xsl:copy>
    </xsl:template>

    <xsl:template match="fault">
        <xsl:copy>
            <xsl:variable name="q" as="xs:QName" select="resolve-QName(., .)" />
            <xsl:attribute name="{local-name-from-QName(q)}" namespace="namespace-uri-from-QName(q)">blah</xsl:attribute>
            <xsl:value-of select="." />
        </xsl:copy>
    </xsl:template>

Michael Kay
Saxonica

Hi Folks,

I want to transform the <fault> element in this document:

<Test xmlns:soap="http://www.soap.org">
     <fault>soap:client</fault>
</Test>

Note that the value of the <fault> element is

soap:client

which is a QName.

I want to transform the <fault> element to this:

<fault soap:client="blah">soap:client</fault>

That is, make the QName value an attribute and assign it the string "blah."

After transformation the XML document is to be this:

<Test xmlns:soap="http://www.soap.org">
     <fault soap:client="blah">soap:client</fault>
</Test>

I tried this code:

     <xsl:template match="fault">
         <xsl:copy>
             <xsl:variable name="QName" select="." />
             <xsl:attribute name="{$QName}">blah</xsl:attribute>
             <xsl:value-of select="." />
         </xsl:copy>
     </xsl:template>

But it produces this error message:

Undeclared prefix in attribute name: soap

What is the proper way to accomplish the desired transformation please?

/Roger