Subject: Re: XPath 1.0 Expression to Test for 3 Digit Number
From: Michael Kay <mike@xxxxxxxxxxxx>
Date: Tue, 08 May 2012 22:26:38 +0100
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Dimitre's solution will accept '0500', mine will not. I took the
requirement to have three digits literally.
Michael Kay
Saxonica
On 08/05/2012 21:31, Dimitre Novatchev wrote:
floor(.) = number(.) and number(.)> 99 and not(number(.)> 999)
Cheers,
Dimitre
On Tue, May 8, 2012 at 1:15 PM, Michael Kay<mike@xxxxxxxxxxxx> wrote:
translate(., '0123456789', '9999999999') = '999' and number(.)> 99
Michael Kay
Saxonica
On 08/05/2012 21:07, Don Smith wrote:
I need an XPath 1.0 expression that will test a node and return a
boolean if the node content is a 3 digit number (i.e., 100-999) and
false if it's anything else.
The catch is this expression won't
be in a transformation so I can't use variables or other additional
constructs. All I get is one expression. I've tried this
*[(string(number(.)) !='NaN')]
and
obtained the number that I need. But I can't get any sort of compare to
work that makes the number be more than 99 and less than 1,000.
Thanks
Don
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Michael Kay - 8 May 2012 20:15:55 -0000
- Dimitre Novatchev - 8 May 2012 20:32:04 -0000
- Michael Kay - 8 May 2012 21:26:51 -0000 <=
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