Subject: how can I rewrite it so I have a variable for year
From: "Murray McDonald" <m.mcdonald@xxxxxxxxx>
Date: Fri, 6 Jan 2012 14:27:27 -0500
|
This is how to pass the year as a parameter to the month template.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:import href="../utilities/date-time.xsl"/>
<xsl:template match="data/menu">
<div id="firstpane" class="menu_list">
<xsl:apply-templates select="year" />
</div>
</xsl:template>
<xsl:template match="year">
<p class="menu_head"> <xsl:value-of select="@value"/> </p>
<div class="menu_body">
<xsl:apply-templates select="month">
<xsl:with-param name="theYear" select="@value"/>
</xsl:apply-templates>
</div>
</xsl:template>
<xsl:template match="month">
<xsl:param name="theYear" select="'Year not provided'"/>
<a href="{$root}/dagboek/{$theYear}/{@value}/1" >
<xsl:call-template name="format-date">
<xsl:with-param name="date" select="concat('2222','-',@value,'-01')"/>
<xsl:with-param name="format" select="'M'"/>
</xsl:call-template>
</a>
</xsl:template>
</xsl:stylesheet>
|