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Hi,
On 11/7/2011 12:32 PM, Michael Kay wrote: On 11/4/2011 9:27 PM, G. Ken Holman wrote:The current() function returns that node that was current at the beginning of the evaluation of the XPath expression. I suppose that's understandable, inasmuch as XSLT 2.0 in general is being pulled in the direction of a generalized data processing language and not just a tree transformation language. (What with xsl:for-each no longer selecting -- or, some day, template rules no longer matching -- only nodes.) Yet I dare say it may help to keep a rough distinction in mind in any case. So does this also mean the concepts of "current node list" etc. go by the boards? (Now going to look and see.) Cheers, Wendell ====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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