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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: rearranging nodes using XSLT
 How can I rearrange nodes in xslt? Remember you are creating a new arrangement of nodes, you are not rearranging the old nodes. My source XML looks something like this: I am trying to rearrance tbd1, tbd2, tbd3 in that order Then simply process them in that order where you find them grouped. I hope the answer below helps. It creates the structure you cite as your desired output. . . . . . . . . . . . Ken T:\ftemp>type akusa.xml
<root>
<list1>
<item1>
<para>sample</para>
</item1>
<tbd2><para>test1</para></tbd2>
<tbd1><para>test1</para></tbd1>
<list2>
<item1>
<para>sample</para>
</item1>
<tbd3><para>test1</para></tbd3>
<tbd1><para>test1</para></tbd1>
<item1>
<para>sample</para>
</item1>
</list2>
</list1>
</root>T:\ftemp>call xslt2 akusa.xml akusa.xsl
<?xml version="1.0" encoding="UTF-8"?>
<root>
<list1>
<item1>
<para>sample</para>
</item1>
<tbd1>
<para>test1</para>
</tbd1>
<tbd2>
<para>test1</para>
</tbd2>
<list2>
<item1>
<para>sample</para>
</item1>
<tbd1>
<para>test1</para>
</tbd1>
<tbd3>
<para>test1</para>
</tbd3>
<item1>
<para>sample</para>
</item1>
</list2>
</list1>
</root>
T:\ftemp>type akusa.xsl
<?xml version="1.0" encoding="US-ASCII"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0"><xsl:output indent="yes"/> <xsl:template match="*[tbd1|tbd2|tbd3]">
<xsl:copy>
<xsl:apply-templates select="@*"/><!--find each group of elements in which a sequence of target elements are found--> <xsl:for-each-group select="*" group-starting-with="*[not(self::tbd1 | self::tbd2 | self::tbd3 )]"> <!--first put out all of those that are not in the group, then put out the group of target elements in the desired order--> <xsl:apply-templates select="current-group() [not(self::tbd1 | self::tbd2 | self::tbd3 )], current-group()[self::tbd1], current-group()[self::tbd2], current-group()[self::tbd3]"/> </xsl:for-each-group> </xsl:copy> </xsl:template> <xsl:template match="@*|node()"><!--identity for all other nodes-->
<xsl:copy>
<xsl:apply-templates select="@*,node()"/>
</xsl:copy>
</xsl:template></xsl:stylesheet> <root> <list1> <item1> <para>sample</para> </item1> <tbd2><para>test1</tbd2> <tbd1><para>test1</tbd1> <list2> <item1> <para>sample</para> </item1> <tbd3><para>test1</tbd3> <tbd1><para>test1</tbd1> <item1> <para>sample</para> </item1> </list2> </list1> </root> -- XSLT/XQuery/XPath training after http://XMLPrague.cz 2010-03-15/19 XSLT/XQuery/XPath training: San Carlos, California 2010-04-26/30 Vote for your XML training: http://www.CraneSoftwrights.com/s/i/ Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Training tools: Comprehensive interactive XSLT/XPath 1.0/2.0 video Video lesson: http://www.youtube.com/watch?v=PrNjJCh7Ppg&fmt=18 Video overview: http://www.youtube.com/watch?v=VTiodiij6gE&fmt=18 G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Male Cancer Awareness Nov'07 http://www.CraneSoftwrights.com/s/bc Legal business disclaimers: http://www.CraneSoftwrights.com/legal 
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