RE: Dynamic Input file path on document method
I can't hard code the static path in xslt. I am asking dynamic path. I can use any path for input file for the transformation. I need to use dynamic input file path on this document method. URL for the document method is input file's path. -----Original Message----- From: Andrew Welch [mailto:andrew.j.welch@xxxxxxxxx] Sent: Thursday, December 03, 2009 8:16 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: Dynamic Input file path on document method document('comments.xml', /) 2009/12/3 Ramkumar <ramkumar@xxxxxxxxxxxxxxxxxx>: > How to use as a second argument in my code? Please share your idea. > > -----Original Message----- > From: Andrew Welch [mailto:andrew.j.welch@xxxxxxxxx] > Sent: Thursday, December 03, 2009 7:57 PM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: Dynamic Input file path on document method > > 2009/12/3 Ramkumar <ramkumar@xxxxxxxxxxxxxxxxxx>: >> Hi List, >> >> When using "document('comments.xml')", xslt looking default path for >> comments.xml' on xslt path. Actually I have it in input file path. >> >> So how to implement the dynamic input path on this code. Please suggest > your >> idea.put > > You can supply a node from the input as second arg to the document() > function, and then it will be resolved against that. > > http://www.w3.org/TR/xslt20/#function-document > > > > > -- > Andrew Welch > http://andrewjwelch.com > Kernow: http://kernowforsaxon.sf.net/ > > -- Andrew Welch http://andrewjwelch.com Kernow: http://kernowforsaxon.sf.net/
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