Re: [xsl] XPath problem with getting all ancestors

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Subject: Re: XPath problem with getting all ancestors
From: Jostein Austvik Jacobsen <josteinaj@xxxxxxxxx>
Date: Fri, 23 Oct 2009 16:25:25 +0200

The actual template does more than copying; it uses recursion to group sections started by headlines at different levels defined by its attributes. I got it from this post: http://www.biglist.com/lists/lists.mulberrytech.com/xsl-list/archives/200910/msg00228.html

The function works really well (except for cases when a headline level is skipped). So if its possible to keep copying the nodes it would be great; otherwise I'll have to fix the function (I'm thinking of expanding the recursion into four xls:for-each-group statements - it's not allowed to go deeper anyway).

I'll do sone further testing once I get back to the computer.

Regards
Jostein

Den 23. okt. 2009 kl. 15.20 skrev "Michael Kay" <mike@xxxxxxxxxxxx>:

   <xsl:template match="article">
       <xsl:variable name="v1">
           <xsl:copy-of select="content/node()"/>
       </xsl:variable>
       <xsl:sequence select="mf:group($v1/node())"/>
   </xsl:template>
As I suspected, you are copying the nodes, and the copies do not have the same ancestors.

It's not clear to me WHY you are copying them - it seems quite unnecessary.

Regards,
Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay

Current Thread
Re: XPath problem with getting all ancestors, (continued) Jostein Austvik Jacobsen - 23 Oct 2009 12:13:05 -0000 Martin Honnen - 23 Oct 2009 12:13:52 -0000 ac - 23 Oct 2009 13:16:14 -0000 Michael Kay - 23 Oct 2009 13:20:54 -0000 Jostein Austvik Jacobsen - 23 Oct 2009 14:25:57 -0000 <= Vyacheslav Sedov - 23 Oct 2009 15:42:59 -0000

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