|
[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] select/except based on position()
I would like to generate a sequence of numbers. @no contains a number. $num the item position not to be included. The following works: select="/items/item/@no except /items/item[$num]/@no" But I would like to base the selection on position(). The following first step of the new solution is also working: select="/items/item[position() != $num]/@no" Now, I would like to drop @no. I only made it up because I couldn't solve my problem without it. @no contains the position of the item! The following is the closed I have been able to get so far, but it doesn't work: select="/items/item[position() != $num]/position()" This is what I want: For an item, return the item positions of the other items. Any hints for how to change the select statement? Cheers, Jesper
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|






