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Re: xsl-for-each-group in xslt 2.0

Subject: Re: xsl-for-each-group in xslt 2.0
From: Martin Honnen <Martin.Honnen@xxxxxx>
Date: Mon, 28 Sep 2009 17:03:00 +0200
Re:  xsl-for-each-group in xslt 2.0
a kusa wrote:

My XML is as follows:


Every <listX><listitem> combination corresponds to one step.

So I want this to transform into:

<step1>A B</step1>
<step2>C D</step2>

I am not sure you need xsl:for-each-group, for the above input (wrapped in a root element) the following stylesheet creates above output (wrapped in a root element):


<xsl:output indent="yes"/>

  <xsl:template match="root">

  <xsl:template match="*[matches(local-name(), 'list[0-9]+')]">
    <xsl:element name="step{substring-after(local-name(), 'list')}">
      <xsl:value-of select="listitem"/>

<xsl:template match="text()"/>



	Martin Honnen

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