Subject: Re: Getting sibling nodes from unique values
From: Mike Ferrari <mikeferrari8@xxxxxxxxx>
Date: Tue, 4 Aug 2009 12:34:20 -0500
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Sweet!
That will teach me to stop overcomplicating things!
Thanks a TON!!
This is the xsl that i ended up with...
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
<xsl:output method="xml"/>
<xsl:template match="/">
<xsl:for-each-group select="Root/row" group-by="company">
<xsl:result-document href="{current-grouping-key()}.xml">
<Root>
<xsl:copy-of select="current-group()"/>
</Root>
</xsl:result-document>
</xsl:for-each-group>
</xsl:template>
</xsl:stylesheet>
On Tue, Aug 4, 2009 at 10:27 AM, Martin Honnen<Martin.Honnen@xxxxxx> wrote:
> Mike Ferrari wrote:
>
>> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>> version="2.0">
>> <xsl:output method="text"/>
>> <xsl:template match="/">
>> <xsl:for-each select="distinct-values(//company)">
>
> Use
> <xsl:for-each-group select="Root/row" group-by="company">
> <xsl:result-document href="{current-grouping-key()}.xml">
> <Root>
> <xsl:copy-of select="current-group()"/>
> </Root>
> </xsl:result-document>
> </xsl:for-each-group>
>
>
>
>
> --
>
> Martin Honnen
> http://msmvps.com/blogs/martin_honnen/
>
>
--
/dev/mike0
http://www.mikeferrari.com
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