RE: Need test for preceding-sibling
Now I see that I over-simplified the problem. The XSLT also has to suppress any <a1> that is not paired with an <a2>. So, I'm not sure the grouping works in your example since there could be two <a1/> elements that are in the group that ends with <a2/>. But, if you specify: <xsl:for-each-group select="*" group-starting-with="a1" group-ending-with="a2"> will that consider "<a1/><a1/><a2/>" a group? Dave -----Original Message----- From: Hintz, David L [mailto:david.hintz@xxxxxxxxxxx] Sent: Thursday, April 23, 2009 1:36 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: Need test for preceding-sibling Thanks, Ken! I should have been clearer in my description. Each <a1> and <a2> should be paired, even though there may be intervening tags. However, an <a2> without its paired <a1> should not be processed. I'll try your grouping solution. Dave -----Original Message----- From: G. Ken Holman [mailto:gkholman@xxxxxxxxxxxxxxxxxxxx] Sent: Thursday, April 23, 2009 1:26 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: Need test for preceding-sibling At 2009-04-23 14:01 -0400, Hintz, David L wrote: >I have a structure like this: > ><a1/> ><a2/> ><a1/> ><a2/> ><b/> ><c/> ><a2/> ><a1/> ><a2/> > >I need to ensure that each <a2> has a preceding <a1>, although there >may be intervening tags. This description is a bit imprecise ... do you need them paired, or will any <a1> before an <a2> suffice? I ask because in the example you have every <a2> has a preceding <a1>, some with intervening tags and some without. But it isn't true that every <a2> has a preceding <a1> that follows any preceding <a2>. >I know that > > name(preceding-sibling::* > >gives me the name of the first preceding sibling, but how do I >construct a test that gives me only the first preceding <a1> or <a2> tag? You shouldn't be working with name() because that deals with strings and not expanded node names in a namespace-safe fashion. The test that there is any <a1> before the current node being <a2> is: preceding-sibling::a1 The test that there is an <a1> correspondingly before every <a2> is approached more easily with XSLT 2 grouping from the parent of those siblings: <xsl:for-each-group select="*" group-ending-with="a2"> <xsl:if test="not(current-group()/self::a1)"> Error! No corresponding a1 for the given a2 </xsl:if> </xsl:for-each-group> I hope this helps. . . . . . . . . . . . . Ken -- XSLT/XSL-FO/XQuery hands-on training - Los Angeles, USA 2009-06-08 Training tools: Comprehensive interactive XSLT/XPath 1.0/2.0 video Video lesson: http://www.youtube.com/watch?v=PrNjJCh7Ppg&fmt=18 Video overview: http://www.youtube.com/watch?v=VTiodiij6gE&fmt=18 G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Male Cancer Awareness Nov'07 http://www.CraneSoftwrights.com/s/bc Legal business disclaimers: http://www.CraneSoftwrights.com/legal
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