Re: Problem with <xsl:if>

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Subject: Re: Problem with <xsl:if>
From: Martin Honnen <Martin.Honnen@xxxxxx>
Date: Sun, 05 Apr 2009 13:01:04 +0200

Pierluigi Fabbris wrote:

                <xsl:if test="./ricetta/@id =vino_consigliato/@ricetta">
                               <xsl:value-of
select="/ricettario/vino_consigliato/@text()"/>
                </xsl:if>

I think instead of the xsl:if and xsl:value-of you simply want <xsl:value-of select="/ricettario/vino_consigliato[@ricetta = current()/@id]"/> That would output the string value of that "vino_consigliato" element for which the "ricetta" attribute is equal to the "id" attribute of the current "ricetta" element.

--

	Martin Honnen
	http://JavaScript.FAQTs.com/

Current Thread
Problem with <xsl:if> Pierluigi Fabbris - 4 Apr 2009 15:12:24 -0000 Michael Kay - 4 Apr 2009 15:19:30 -0000 <Possible follow-ups> Pierluigi Fabbris - 5 Apr 2009 10:49:55 -0000 Martin Honnen - 5 Apr 2009 11:01:28 -0000 <= mozer - 5 Apr 2009 11:20:44 -0000 Michael Kay - 5 Apr 2009 12:48:54 -0000

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